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Reading battery status using bq27200
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nightfire
2010-04-19 , 04:00
Posts: 310 | Thanked: 383 times | Joined on Jan 2010
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8
Ah, gotcha.
Voltage drop across a 20mOhm resistor.
If my math's right, that means a value of 1000 represents 179mA, which is much more believable.
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