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	bandora	2012-12-04 , 01:48
	Posts: 1,338 \| Thanked: 1,055 times \| Joined on Oct 2009 @ California, USA / Jordan	#1

Hey,

So I am taking a basic Python class and one of my assignments was to create a very simple calculator..

Btw, I am using Python 2.3 (As that's what the teacher wants us to use because of livewires)

It's very simple, but I am experiencing an error that I don't know how to fix (which is probably too simple for you guys to fix haha).. So I am getting this error on IDLE:

Traceback (most recent call last):
File "C:/Python23/calculator", line 38, in -toplevel-
a.retry()
File "C:/Python23/calculator", line 32, in retry
Calculator.calc()
TypeError: unbound method calc() must be called with Calculator instance as first argument (got nothing instead)

I don't know how to fix it, I've tried multiple things and I couldn't get it to work.. Here's the code:

Code:

import sys

class Calculator(object):
    def calc(self):
        x = int(input("Please enter the first number: "))
        y = int(input("Please enter the second number: "))
        #op = Operator
        op = str.lower(raw_input(
              "Please enter what method you want to use ((A)ddition, (S)ubtraction, (M)ultiplication, (D)ivision) or type 'end' to quit: "))
        if op != "a"  and op != "s" and op != "m" and op != "d" and op != "end":
            exit = str.lower(raw_input("Are you sure you want to exit calculator (Yes or No)? "))
            if exit == "yes":
                sys.exit(0)
            else:
                calc()
        else:
            if op == "a":
                print ("\nThe result is: ", x, "+", y, "=", str(x+y))
    
            elif op == "s":
                print ("\nThe result is: ", x, "-", y, "=", str(x-y))

            elif op == "m":
                print ("\nThe result is: ", x, "*", y, "=", str(x*y))

            elif op == "d":
                print ("\nThe result is: ", x, "/", y, "=", str(float(x)/float(y)))

    def retry(self):
        confirm = str.lower(raw_input("Would you like to do another calculation (Yes or No)? "))
        if confirm == "yes":
            Calculator.calc()
        else:
            sys.exit(0)

a = Calculator()
a.calc()
a.retry()


raw_input("\nPress any key to exit.")

If you guys can help me on this one that would be great.. I am just curious on how to fix this small issue.

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Last edited by bandora; 2012-12-04 at 02:01.

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	bandora	2012-12-04 , 01:58
	Posts: 1,338 \| Thanked: 1,055 times \| Joined on Oct 2009 @ California, USA / Jordan	#2

Okay fixed the first error:

But I am getting another error if I choose "No" when it asks me to do another calculation:

Traceback (most recent call last):
File "C:/Python23/calculator", line 41, in -toplevel-
a.retry()
File "C:/Python23/calculator", line 37, in retry
sys.exit(0)
SystemExit: 0

Here's the new code (I put what I changed in bold):

Code:

import sys



class Calculator(object):
    def calc(self):
        x = int(input("Please enter the first number: "))
        y = int(input("Please enter the second number: "))
        #op = Operator
        op = str.lower(raw_input(
            "Please enter what method you want to use ((A)ddition, (S)ubtraction, (M)ultiplication, (D)ivision) or type 'end' to quit: "))
        if op != "a"  and op != "s" and op != "m" and op != "d" and op != "end":
            exit = str.lower(raw_input("Are you sure you want to exit calculator (Yes or No)? "))
            if exit == "yes":
                sys.exit(0)
            else:
                calc()
        else:
            if op == "a":
                print ("\nThe result is: ", x, "+", y, "=", str(x+y))
    
            elif op == "s":
                print ("\nThe result is: ", x, "-", y, "=", str(x-y))

            elif op == "m":
                print ("\nThe result is: ", x, "*", y, "=", str(x*y))

            elif op == "d":
                print ("\nThe result is: ", x, "/", y, "=", str(float(x)/float(y)))

    def retry(self):
        confirm = str.lower(raw_input("Would you like to do another calculation (Yes or No)? "))
        b = Calculator()
        if confirm == "yes":
            b.calc()
        else:
            sys.exit(0)

a = Calculator()
a.calc()
a.retry()


raw_input("\nPress any key to exit.")

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	marxian	2012-12-04 , 02:03
	Posts: 2,448 \| Thanked: 9,523 times \| Joined on Aug 2010 @ Wigan, UK	#3

In the retry() method,

Code:

Calculator.calc()

should be

Code:

self.calc()

EDIT: No need to create another instance of Calculator, as the existing instance is passed as the argument to both calc() and retry().

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	bandora	2012-12-04 , 06:23
	Posts: 1,338 \| Thanked: 1,055 times \| Joined on Oct 2009 @ California, USA / Jordan	#4

Thanks marxian!

Ah good stuff! I changed the code quite a bit and now it's working like how I want it!

Code:

import sys

class Calculator(object):
    def quit_prompt(self):
            exit = str.lower(raw_input("Are you sure you want to exit calculator (Yes or No)? "))
            if exit == "yes":
                sys.exit()
            else:
                calc()

    def add(self, x, y):
        print "The result is: ", x, "+", y, "=", str(x+y)
    def subt(self, x, y):
        print "The result is: ", x, "-", y, "=", str(x-y)
    def mult(self, x, y):
        print "The result is: ", x, "*", y, "=", str(x*y)
    def div(self, x, y):
        print "The result is: ", x, "/", y, "=", str(float(x)/float(y))
        
    def calc(self):
        x = int(input("Please enter the first number: "))
        y = int(input("Please enter the second number: "))
        #op = Operator
        op = str.lower(raw_input(
            "Please enter what method you want to use ((A)ddition, (S)ubtraction, (M)ultiplication, (D)ivision) or type 'end' to quit: "))  
        while op != "end":
            if op == "a":
                self.add(x, y)
    
            if op == "s":
                self.subt(x, y)

            if op == "m":
                self.mult(x, y)
    
            if op == "d":
                self.div(x, y)
            self.retry()
            break
        

    def retry(self):
        confirm = str.lower(raw_input("\nWould you like to do another calculation (Yes or No)? "))
        if confirm == "yes":
            self.calc()
        else:
            pass

a = Calculator()
a.calc()

print "\nThank you for using the calculator!"
raw_input("\nPress any key to exit.")

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Last edited by bandora; 2012-12-04 at 07:45. Reason: Fixed all the errors yay me! :) Thanks marxian!

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	bandora	2012-12-16 , 02:39
	Posts: 1,338 \| Thanked: 1,055 times \| Joined on Oct 2009 @ California, USA / Jordan	#5

EDITED: Nvm, I solved the new issue by myself! Props to me! lol

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Last edited by bandora; 2012-12-16 at 03:04.

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udaychaitanya16	2012-12-16 , 08:07
Posts: 212 \| Thanked: 66 times \| Joined on May 2010 @ India	#6

Thats great.

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bandora

	Dave999	2012-12-16 , 09:38
	Posts: 7,075 \| Thanked: 9,073 times \| Joined on Oct 2009 @ Moon! It's not the East or the West side... it's the Dark Side	#7

Great bandora. Python rules. Why not adjust it and add a gui and release it for your favorite device? Or are you unly looking to learn python syntax?

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Last edited by Dave999; 2012-12-16 at 19:17.

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	bandora	2012-12-16 , 18:11
	Posts: 1,338 \| Thanked: 1,055 times \| Joined on Oct 2009 @ California, USA / Jordan	#8

Well I am taking a Python class, so all this is pretty much just for learning purposes.. And the edited post was about another code.. I am making a simple python game using pygame and livewires (it's my final), so far so good lol...

I absolutely love TMO on this matter! Like it's pretty much guaranteed you're gonna get helped developing anything! Thanks again!

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