Active Topics

 


Page 1 of 2 1 2
Reply
Thread Tools
insanelysexy is offline insanelysexy
2017-02-27 , 13:08
Posts: 112 | Thanked: 116 times | Joined on Apr 2012
#1
I have attached a 4000mah battery on Intex Aqua Fish. There are some issues that I am facing.

1. Reported voltage is not matching the measured one. Right now: reported: 3.84 V
measured: 3.96V.

2. 2500mah original battery and 4000mah extra one always some voltage difference.

3. Original one gets charged a lot quicker than 4000mah one. Can i use a charger + - to directly connect 4000mah battery's + - to charge it ?
 

The Following 2 Users Say Thank You to insanelysexy For This Useful Post:
pichlo's Avatar
pichlo is offline pichlo
2017-02-27 , 13:15
Posts: 6,453 | Thanked: 20,983 times | Joined on Sep 2012 @ UK
#2
Originally Posted by insanelysexy View Post
I have attached a 4000mah battery on Intex Aqua Fish. There are some issues that I am facing.

1. Reported voltage is not matching the measured one. Right now: reported: 3.84 V
measured: 3.96V.
This is merely a speculation but could it be explained by some circuitry between the battery terminals and the point where the voltage is measured? If the difference stays contact at different charge levels, that would be a good indicator.

2. 2500mah original battery and 4000mah extra one always some voltage difference.
That would also point in the same direction.

3. Original one gets charged a lot quicker than 4000mah one. Can i use a charger + - to directly connect 4000mah battery's + - to charge it ?
Of course the bigger battery charges slower, it is double the capacity! A twice as large bucket will also take twice as long to fill up from the same tap.

I am not sure what you mean by charger+-. The phone is charged through the USB port, right? Do you mean cutting the USB wires and connecting them directly to the battery terminals? That would be a sure way of killing the battery (and maybe losing an eye in the process, if the battery explodes in your face).
__________________
Русский военный корабль, иди нахуй!
 

The Following 3 Users Say Thank You to pichlo For This Useful Post:
insanelysexy is offline insanelysexy
2017-02-27 , 13:32
Posts: 112 | Thanked: 116 times | Joined on Apr 2012
#3
Originally Posted by pichlo View Post
This is merely a speculation but could it be explained by some circuitry between the battery terminals and the point where the voltage is measured? If the difference stays contact at different charge levels, that would be a good indicator.

Voltage is measured at the terminal of the battery, just before connecting it to the phone. And "Btry" shows fluctuating voltage. Like batterymeter for N900. But seems to work okay.




Of course the bigger battery charges slower, it is double the capacity! A twice as large bucket will also take twice as long to fill up from the same tap.

I am not sure what you mean by charger+-. The phone is charged through the USB port, right? Do you mean cutting the USB wires and connecting them directly to the battery terminals? That would be a sure way of killing the battery (and maybe losing an eye in the process, if the battery explodes in your face).
Yes, thats what I meant and now feeling stupid about it.
 

The Following 3 Users Say Thank You to insanelysexy For This Useful Post:
elros34 is offline elros34
2017-02-27 , 13:45
Posts: 578 | Thanked: 994 times | Joined on Dec 2012
#4
Measuring voltage without load is pointless as it will drop. The higher current the higher voltage drop.
Btry use power supply kernel interface.
 

The Following User Says Thank You to elros34 For This Useful Post:
juiceme is offline juiceme
2017-02-27 , 13:49
Community Council | Posts: 4,920 | Thanked: 12,867 times | Joined on May 2012 @ Southerrn Finland
#5
Ahh, so you measure the battery separately before connecting to phone!?

Of course the unloaded voltage is different from loaded voltage, those will really have nothing in common!
Same thing explains what you call fluctuation; the current that the device draws any given moment changes all the time, hence the internal resistance and current sourcing capacity of the battery defines what is the terminal voltage at that time...
 

The Following 2 Users Say Thank You to juiceme For This Useful Post:
lal is offline lal
2017-02-27 , 15:22
Posts: 114 | Thanked: 381 times | Joined on Jan 2014
#6
oh well, and the accuracy of meter matters too.

On a different note, wouldn't the meter be more accurate (assuming it's not a cheap Chinese one and measured under similar condition that it is loaded). How accurately could a phone measure?
 

The Following User Says Thank You to lal For This Useful Post:
juiceme is offline juiceme
2017-02-27 , 15:34
Community Council | Posts: 4,920 | Thanked: 12,867 times | Joined on May 2012 @ Southerrn Finland
#7
Originally Posted by lal View Post
oh well, and the accuracy of meter matters too.

On a different note, wouldn't the meter be more accurate (assuming it's not a cheap Chinese one and measured under similar condition that it is loaded). How accurately could a phone measure?
Metering accuracy is not really a concern in voltage measurement; there are quite a few other things to consider. Perhaps having a good stability long-time reference is the most important thing.

Measurement is pretty rarely just "direct D/A conversion, at least when there is any sense in the system as that is about the most inaccurate way to do it (albeit it is a fast measurement, and now we are talking Msamples/s even on cheap systems)
The right way to do it is to have an integrating measurement, where a capacitor is repeatedly charged and discharged through a resistance and the cycle time is measured. Just about all DMM's use this method.
 

The Following 2 Users Say Thank You to juiceme For This Useful Post:
pichlo's Avatar
pichlo is offline pichlo
2017-02-27 , 16:01
Posts: 6,453 | Thanked: 20,983 times | Joined on Sep 2012 @ UK
#8
Originally Posted by juiceme View Post
Ahh, so you measure the battery separately before connecting to phone!?
THAT seems to be the right question. I had not even considered that possibility, knowing that it would obviously give different results.

Originally Posted by juiceme View Post
The right way to do it is to have an integrating measurement, where a capacitor is repeatedly charged and discharged through a resistance and the cycle time is measured. Just about all DMM's use this method.
I always considered the integrating method a fudge, to replace an expensive 12 or 16 bit ADC with a cheap comparator and a counter. But now you mention it, it does have some advantages too
__________________
Русский военный корабль, иди нахуй!
 

The Following User Says Thank You to pichlo For This Useful Post:
insanelysexy is offline insanelysexy
2017-02-27 , 17:31
Posts: 112 | Thanked: 116 times | Joined on Apr 2012
#9
Originally Posted by pichlo View Post
THAT seems to be the right question. I had not even considered that possibility, knowing that it would obviously give different results.

Yes I measured the voltage BOTH times. Once before connecting the battery and then on different intervals, with phone on and working. Results are the same.
 

The Following User Says Thank You to insanelysexy For This Useful Post:
insanelysexy is offline insanelysexy
2017-02-27 , 17:34
Posts: 112 | Thanked: 116 times | Joined on Apr 2012
#10
Originally Posted by juiceme View Post
Ahh, so you measure the battery separately before connecting to phone!?
Both before connecting the battery and then while using the phone.
 

The Following 2 Users Say Thank You to insanelysexy For This Useful Post:
Reply
Page 1 of 2 1 2

« Previous Thread | Next Thread »

 
Forum Jump


All times are GMT. The time now is 13:17.

Contact Us - Home - Archive - Top