Active Topics
-
Firefox with Leste (10)
to Maemo 7 / Leste by teroyk - 3 days, 11 hrs ago - more...
|
2010-02-10
, 08:38
|
|
Posts: 432 |
Thanked: 645 times |
Joined on Mar 2009
|
#2
|
Hi,
this is a python unicode-problem. There is a good howto on that. But in general this should do it:
Daniel
this is a python unicode-problem. There is a good howto on that. But in general this should do it:
Code:
self.ui.listTubeLine.currentItem().text().encode('ascii','ignore')
| The Following User Says Thank You to danielwilms For This Useful Post: | ||
|
|
2010-02-10
, 09:16
|
|
Posts: 127 |
Thanked: 54 times |
Joined on Nov 2009
|
#3
|
Excellent - I'll give that a shot tonight. many thanks.
|
|
2010-02-10
, 20:21
|
|
Posts: 127 |
Thanked: 54 times |
Joined on Nov 2009
|
#4
|
Hmm - tried that but got an error that QList doesn't have a .encode attribute.
I found .toAscii() instead and used that - but it's still not working. I get a similar error as previously although it would appear to be an ascii string rather than unicode as I'm not getting the u beforehand.
Where as the following works fine:
So the key must be in the dictionary - still an ascii to unicode issue?
I found .toAscii() instead and used that - but it's still not working. I get a similar error as previously although it would appear to be an ascii string rather than unicode as I'm not getting the u beforehand.
Code:
for Station in TubeStationList[self.ui.listTubeLine.currentItem().text().toAscii()].values():
KeyError: PyQt4.QtCore.QByteArray('district')
Code:
for Station in TubeStationList['district'].values():
I've been following the excellent guide of how to create apps with python / Qt. I've got an issue which I hope somebody can resolve. I have a python app that gets tube details etc - and I'm trying to give it a nice front end.
When I try to assign a dictionary value I get the following error:
Thanks in advance