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pichlo is offline pichlo
2014-11-06 , 10:27
Posts: 6,453 | Thanked: 20,983 times | Joined on Sep 2012 @ UK
#1
I am talking about the app that I am developing. Some operations can take a vvvveeeeerrrrrryyy long time (up to a few minutes) and the damn watchdog just reboots the damn phone. I know about the R&D mode (BTW, it seems all the links to the R&D mode wiki page are dead) but I cannot ask the users of my app to enable the R&D mode just to be able to use it, can I?

I assume there is a system call somewhere that I can call periodically to reset the watchdog. What is it?

Sorry if this is a silly question with an obvious answer. I must be particularly slow this morning. I just spent two hours searching and found nothing of relevance.
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peterleinchen is offline peterleinchen
2014-11-06 , 12:30
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#2
@pichlo
Huh, what kind of app is 'that'? Taking all resources away?
Did you try with 'nice -n 19 app'?
Or maybe if it is IO consuming, then 'nice -n 19 ionice -c 3 -n 7 app'?

Hope this is sufficient to let the watchdog bite/kick in.

About wtachdog calls from within app IDK ...
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pichlo's Avatar
pichlo is offline pichlo
2014-11-06 , 12:39
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#3
It is a GUI app that, depending on settings, may want to fill up a large (200MB+) buffer with data generated at runtime. In pseudocode...
Code:
for (int i; i < 200MB; ++i)
  buffer[i] = fx(i);
fx() can be quite a complex function and running it 200M times can take up to a few minutes.
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reinob is offline reinob
2014-11-06 , 12:45
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#4
Originally Posted by pichlo View Post
It is a GUI app that, depending on settings, may want to fill up a large (200MB+) buffer with data generated at runtime. In pseudocode...
Code:
for (int i; i < 200MB; ++i)
  buffer[i] = fx(i);
fx() can be quite a complex function and running it 200M times can take up to a few minutes.
$ man sched_yield

add #include <sched.h>

and do something along the lines of:

Code:
for (int i; i < 200MB; ++i) {
  if(i % 1000 == 0) sched_yield();
  buffer[i] = fx(i);
}
If that's too ugly for you you could measure the elapsed time (at every iteration, or after N interations) and only when the time is greater than some threshold, you call sched_yield().
 

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traysh is offline traysh
2014-11-06 , 12:46
Posts: 324 | Thanked: 739 times | Joined on Jun 2009 @ São Paulo, Brazil
#5
Originally Posted by pichlo View Post
It is a GUI app that, depending on settings, may want to fill up a large (200MB+) buffer with data generated at runtime. In pseudocode...
Code:
for (int i; i < 200MB; ++i)
  buffer[i] = fx(i);
fx() can be quite a complex function and running it 200M times can take up to a few minutes.
Do the complex job in another thread.
 
peterleinchen's Avatar
peterleinchen is offline peterleinchen
2014-11-06 , 12:51
Posts: 4,118 | Thanked: 8,901 times | Joined on Aug 2010 @ Ruhrgebiet, Germany
#6
Yes, that will let the WD bite, for sure!

Did you try above suggestion?
May slow down a bit more, but for sure should leave enough resources to let the WD kick...

@was/am on slow line: that would have been my next suggestion: a sleep inside the loop every 100th call or so. But reinob gave already the (better) idea!
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Last edited by peterleinchen; 2014-11-06 at 13:06.
 

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pichlo is offline pichlo
2014-11-06 , 12:55
Posts: 6,453 | Thanked: 20,983 times | Joined on Sep 2012 @ UK
#7
Originally Posted by traysh View Post
Do the complex job in another thread.
It is already in another thread. If you mean creating a new thread each time I call fx(), then no, thank you.

Originally Posted by reinob View Post
$ man sched_yield
Thanks, exactly what I needed. Going to give it a try.

EDIT:
Originally Posted by peterleinchen View Post
a sleep inside the loop every 100th call or so
That's also not bad. I would call it every Nth second instead of every Nth loop but the idea is sound, thanks.
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Last edited by pichlo; 2014-11-06 at 13:14.
 

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